10f^2+31f=0

Solution for 10f^2+31f=0 equation:

10f^2+31f=0

a = 10; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·10·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*10}=\frac{-62}{20}
=-3+1/10
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*10}=\frac{0}{20}
=0
$